Warning: escapeshellarg() ...what is this?

Discussion in 'PHP' started by unlisted80, Nov 9, 2006.

0
  1. #1
    when i run the script i got this error

    The codes
    show that there is an error on line 39
    what is this error?

    thanks advance
     
    unlisted80, Nov 9, 2006 IP
  2. nico_swd

    nico_swd Prominent Member

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    #2
    Your host might be running PHP in safe mode. You should ask them for info.
     
    nico_swd, Nov 9, 2006 IP
  3. thedark

    thedark Well-Known Member

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    #3
    maybe the host company don't want you to do execute shell commands, for security reasons.
     
    thedark, Nov 11, 2006 IP