VB.NET Class File For Zip a File or Directory

Discussion in 'Programming' started by largn81, Jan 26, 2008.

  1. #1
    This article is used to zip a file or directory using vb.net. The classes and method to zip a file is availale in java.io, java.util, java.util.zip class library.To import these you have to add a reference vsjlib Library in .net component.


    .NET Classes used :


    Imports System.IO
    Imports java.io
    Imports java.util
    Imports java.util.zip

    Introduction


    This article is used to create a zip file in easy way.
    What you have to do is just create an object for the class that i have written in below and call the procedrue CreateZipFile(FolderToZip) or CreateZipFile(FileToZip).



    Class to zip file or directory


    Imports System.IO
    Imports java.io
    Imports java.util
    Imports java.util.zip

    Public Class clsZip

    Public Sub CreateZipFile(ByVal sPath As String)
    Dim fos As java.io.FileOutputStream
    Dim zos As java.util.zip.ZipOutputStream
    Dim di As System.IO.DirectoryInfo

    'check , is it a file existing in this path, if true then zip a file
    If System.IO.File.Exists(sPath) Then
    Dim fInfo As New FileInfo(sPath)

    'create a zip file with same name in the same path
    fos = New java.io.FileOutputStream(sPath.Replace(fInfo.Exten sion, ".zip"))
    zos = New java.util.zip.ZipOutputStream(fos)

    'procedure to zip one File
    ZipOneFile(fos, zos, sPath)

    'check , is it a directory existing in this path,if true then zip a directory
    ElseIf System.IO.Directory.Exists(sPath) Then

    'create a zip file with same name in the same path
    fos = New java.io.FileOutputStream(sPath & ".zip")
    zos = New java.util.zip.ZipOutputStream(fos)
    di = New System.IO.DirectoryInfo(sPath)

    'procedure to zip a directory
    ZipDirectory(fos, zos, di, sPath)
    End If


    zos.close()
    fos.close()
    zos.flush()
    fos.flush()
    End Sub

    Private Sub ZipDirectory(ByVal fos As java.io.FileOutputStream, ByVal zos As java.util.zip.ZipOutputStream, ByVal di As System.IO.DirectoryInfo, ByVal SRootDir As String)
    Dim fis As java.io.FileInputStream
    Dim ze As java.util.zip.ZipEntry

    'to get file info from the directory
    Dim fInfos As System.IO.FileInfo() = di.GetFiles
    Dim fInfo As System.IO.FileInfo

    For Each fInfo In fInfos
    'give the zip entry or the folder arrangement for the file
    ze = New java.util.zip.ZipEntry(fInfo.FullName.Substring(SR ootDir.LastIndexOf("\")))

    'The DEFLATED method is the one of the methods to zip a file
    ze.setMethod(ze.DEFLATED)
    zos.putNextEntry(ze)

    'Input stream for the file to zip
    fis = New java.io.FileInputStream(fInfo.FullName)

    'Copy stream is a simple method to read a file input stream (file to zip) and write it to a file output stream(new zip file)
    CopyStream(fis, zos)

    zos.closeEntry()
    fis.close()
    Next

    'If the directory contains the sub directory the call the same procedure
    Dim dinfos As System.IO.DirectoryInfo() = di.GetDirectories()
    Dim dinfo As System.IO.DirectoryInfo
    For Each dinfo In dinfos
    ZipDirectory(fos, zos, dinfo, SRootDir)
    Next

    End Sub

    Private Sub ZipOneFile(ByVal fos As java.io.FileOutputStream, ByVal zos As java.util.zip.ZipOutputStream, ByVal sFullName As String)
    Dim fis As java.io.FileInputStream
    Dim ze As java.util.zip.ZipEntry
    'give the zip entry or the folder arrangement for the file
    ze = New java.util.zip.ZipEntry(sFullName.Substring(sFullNa me.LastIndexOf("\")))
    'The DEFLATED method is the one of the methods to zip a file
    ze.setMethod(ze.DEFLATED)
    zos.putNextEntry(ze)
    'Input stream for the file to zip
    fis = New java.io.FileInputStream(sFullName)
    'Copy stream is a simple method to read a file input stream (file to zip) and write it to a file output stream(new zip file)
    CopyStream(fis, zos)
    zos.closeEntry()
    fis.close()
    End Sub

    Private Sub CopyStream(ByVal src As java.io.FileInputStream, ByVal dest As java.util.zip.ZipOutputStream)
    Dim reader As New java.io.InputStreamReader(src)
    Dim writer As New java.i:confused:utputStreamWriter(dest)
    While reader.ready
    writer.write(reader.read)
    End While
    writer.flush()
    End Sub


    End Class



    CALL THE PROCEDURE TO ZIP A FILE


    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
    Dim obj As New clsZip
    obj.CreateZipFile(TextBox1.Text)
    MsgBox("New Zip file is created for " & TextBox1.Text, MsgBoxStyle.Information, "Zip File") End Sub



    Step by Step process

    1. Create a new vb.net project
    2. Create a class clsZip
    3. Copy the code CLASS TO ZIP A FILE OR DIRECTORY
    4. In the solution explorer-->Reference, right click,
    select vsjlib library in the .Net library Tab Page.
    5. See the sample CALL THE PROCEDURE TO ZIP A FILE


    Thanx
    ;)
     
    largn81, Jan 26, 2008 IP