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variable issues using includes

Discussion in 'PHP' started by david_sakh, Jan 12, 2005.

  1. #1
    $variable="blah";
    include("file.php"); ?>
    Code (markup):
    this works, allowing the included file to use the variable $variable

    but, I changed my include path to another directory:
    
    $variable="blah";
    include("http://www.site.com/directory/file.php"); ?>
    Code (markup):
    and it no longer works....$variable isn't recongized.
    SEMrush
    Could this be resolved, and how can I refer to other folders above the current directory using a local path not using http://
     
    david_sakh, Jan 12, 2005 IP
    SEMrush
  2. digitalpoint

    digitalpoint Overlord of no one Staff

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    #2
    Reference the file with the file path, not a URL. Doing it as a URL isolates it into it's own script. You would need to know the full path on the server... could be something like:

    /home/sites/site1/www/file or something along those lines.
     
    digitalpoint, Jan 12, 2005 IP
    david_sakh likes this.
  3. david_sakh

    david_sakh Peon

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    #3
    Is this for security reasons?
     
    david_sakh, Jan 12, 2005 IP
  4. anton-io!

    anton-io! Active Member

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    #4
    this is a long shot, but try

    include '/directory/file.php';

    or

    include 'directory/file.php';


    http://ca.php.net/manual/en/function.include.php
     
    anton-io!, Jan 13, 2005 IP
  5. goldensea80

    goldensea80 Well-Known Member

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    #5
    I think, in general, if file.php is not in your server, you CANNOT do it. Because when you request a PHP file from an URL, the server will process that file and return the output.
    If I am not right, so I can easily hack other site by
    inlcude("http://www.theirserver.com/include.inc.php")
    PHP:
     
    goldensea80, Jan 13, 2005 IP
  6. T0PS3O

    T0PS3O Feel Good PLC

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    #6
    Is this correct? I have this issue here:

    http://forums.digitalpoint.com/showthread.php?t=7795

    and this answer might solve my problem. But isn't there a better way to include output from a different page? I basically ned to scrape a file's output.
     
    T0PS3O, Jan 13, 2005 IP
  7. xml

    xml Peon

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    #7
    $pageData = file_get_contents('http://www.feedsfarm.com/');

    This will get the output of the page.
     
    xml, Jan 13, 2005 IP
  8. goldensea80

    goldensea80 Well-Known Member

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    #8
    I think that's correct. However, if your file's extension is not .PHP, that may works.
     
    goldensea80, Jan 13, 2005 IP
  9. david_sakh

    david_sakh Peon

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    #9
    oh, even more help in case i want to see some variables. :)

    I forgot to mention that shawn's solution did work, just use a local path.
     
    david_sakh, Jan 13, 2005 IP