Using opendir() output to populate a drop down form box

I am currently using this script fragment

//using the opendir function to list the files in the directory
$dir_handle = opendir("./$localfolder") or die("Unable to open Directory");
	//echo "$dir_handle";

//running the while loop
while (false !== ($file = readdir($dir_handle))) 
{  
//if($file!="." && $file!="..")   //backup
if($file!="." && $file!=".." && $file!="index.php")
{    
 $name=$file; 
 echo $name;
 echo "<br>";
}
}

Code (markup):

to read the contents of a directory. I would like to populate a dropdown box on an html form with those results so that one item can be selected and submitted.

I am assuming that I will need to array them out and then get it to selection portion. Forms are my weakest point.

Really could use a little help.

 

<?php
//using the opendir function to list the files in the directory
$localfolder = "";
$dir_handle = opendir("./$localfolder") or die("Unable to open Directory");
//echo "$dir_handle";

//running the while loop
while (false !== ($file = readdir($dir_handle)))
{
//if($file!="." && $file!="..") //backup
if($file!="." && $file!=".." && $file!="index.php")
{
$name[]=$file;
}
}
?>

<select name="fileName">
<?php foreach ($name as $filename) { ?>
<option value="<?=$filename;?>"><?=$filename;?></option>
<?php } ?>
</select>

 

Looks like it might work. Let me play with that.

+rep for the effort whether it works or not.