Use variable as an array argument

The value of the variable $numbers is 1, 2, 3, 4, 5 but this code doesn't work:

$wp_query->query(array('post__in'=>array($numbers),'showposts'=>5,'paged'=>$paged));

PHP:

When I type those numbers manually it works:

$wp_query->query(array('post__in'=>array(1, 2, 3, 4, 5),'showposts'=>5,'paged'=>$paged));

PHP:

What is the problem?

 

so $numbers is a string containing the text "1, 2, 3, 4, 5"?

If so, what you're doing is creating an array with a string in it, not what you wanted.

To accomplish that, simply do explode(', ', $numbers) instead:

$wp_query->query(array('post__in'=> explode(', ', $numbers),'showposts'=>5,'paged'=>$paged));

PHP:

 

This code doesn't seem to work...

Here is how I get the $numbers string:

<?php
$post_ids = $wpdb->get_col("SELECT comment_post_ID FROM $wpdb->comments WHERE user_id = $current_user->ID AND comment_approved = '1' ");
$numbers = implode(', ', $post_ids);
?>

PHP:

The first line gets IDs from database and the second line adds , symbol in order to use these numbers as an array argument. Is anything wrong?

 

You don't need to do the implode, remove that line and just do:

$wp_query->query(array('post__in'=> $post_ids,'showposts'=>5,'paged'=>$paged));

PHP:

And if that doesn't work do:

echo "<pre>"; print_r($post_ids); echo "</pre>";

PHP:

and show us the output as I'm not sure how wordpress returns the db results.

 

http://codex.wordpress.org/Function_Reference/wpdb_Class

Yes, that should do it.^

 

It works. Thank you very much!!!