UNIX find and replace inside php files

I have a big list of php files that need a hardcoded path changed
So let's say I want to change /mydir/file.php to /yourdir/file.php, in all the .php files under /home/mydomains/

There must be an easy one-line way using grep or find in UNIX, could anyone suggest it please?

 

I know it isn't what you asked.

You can do it under windows using multi-replace. The downside is you have to add all the files to the list.

 

Thanks but I have linux and 78 websites on which I'd like to change that one line, so I have no other options :/

After some searching I've tried the following:

find /home/admin/domains/mydomain.com/public_html/ -type f | xargs perl -pi -e 's/include\(\'\.\.\/inc\/stuff\.php\'\);/include\(\'\/mylibs\/stuff\.php\'\);/g'

When I use it in SSH though, I get a prompt (??) that apparently is waiting for my input..any idea?
The escapes seem to be ok

 

try:

find /home/admin/domains/mydomain.com/public_html/ -type f | xargs perl -pi -e "s/include\(\'\.\.\/inc\/stuff\.php\'\);/include\(\'\/mylibs\/stuff\.php\'\);/g"

 

lol thanks it worked

 

ls -al /home/asdasd/bsfdsfsd/ | grep .php | xargs mv /home/asdkasdh/mnmsandabs

 

Hey stumbled on this while googling what I was trying to do.
I need to do the same thing but having "issues"
I need to do a find and replace in all ascii files in the current directory and recursively through the sub directories I need to replace
</body>

with
</body><test string here>
but when I try running

find -type f | xargs perl -pi -e "</body>\s+;</body><test\s+string\s+here>'\);/g"

I get:

Backslash found where operator expected at -e line 1, near "</body>\"
(Missing operator before \?)
Bareword found where operator expected at -e line 1, near "s+;</body><test\s+string\s+here"
syntax error at -e line 1, near "</body>\"
Can't find string terminator "'" anywhere before EOF at -e line 1. ​

 

Actually just found the answer myself
find /testdir -type f -exec sed -i 's#</body>#</body><string for you>#g' {} \;

works like a champ