Today or Yesterday from date

Hi guys, could somebody tell me if there is a better way of finding out if a date is "Today" or "Yesterday"? Is there anyway to shorten/speed up the code I already have?

Thanks

$time = $rows['date'];

$lastday = date('m/d/Y',$time);

$today = mktime(0,0,0,date("m"),date("d"),date("Y"));
$yesterday = mktime(0,0,0,date("m"),date("d")-1,date("Y"));
$today = date("m/d/Y", $today);
$yesterday = date("m/d/Y", $yesterday);

if($today == $lastday){$dateposted="Today";}
elseif($yesterday == $lastday) {$dateposted="Yesterday";}
else {$dateposted = $lastday;}

echo $dateposted;

PHP:

 

if you have access to php 5.3 the answer is yes.

Please refer to:

http://de3.php.net/manual/en/class.datetime.php
http://de3.php.net/manual/en/datetime.sub.php


10 days to past:
Object oriented style

<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "\n";
?>

PHP:

Procedural style

<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>

PHP:

 

Ok thanks, but do you think that will work better than my original code?

 

Turns out I don't have php 5.3, I have php 5.2.13. Is there another code I could use instead?

 

$time = $rows['date'];

$lastday = date('m/d/Y', $time);

$today = strtotime("today");
$yesterday = strtotime("yesterday");
$today = date("m/d/Y", $today);
$yesterday = date("m/d/Y", $yesterday);

if ($today == $lastday) {
$dateposted = "Today";
} elseif ($yesterday == $lastday) {
$dateposted = "Yesterday";
} else {
$dateposted = $lastday;
}

echo $dateposted;

PHP:

 

PHP 6 is coming it s more user friendly....