Timestamp for today -> end of today

Hey guys,

I want to find the timestamp at the start of a particular date to the end of that day.
i.e. 00:00:00am-11:59:59pm

How would I do this. For example if I had the date 02:02:2009 (2nd february 2009) how would I get the starting and ending timestamp.

Thanks

 

You can use PHP function mktime

 

// Start of today's server time
echo strtotime(date("Y-m-d 00:00:01"));
// End of today's server time
echo strtotime(date("Y-m-d 23:59:59"));

PHP:

 

@ThePHPMaster - Thanks! It works brilliantly

 

I'm trying to get the timestamp of a date 10 days ago. I got this so far and it works if the date is less than 10 (it will decrease the month by one) but it doesn't work for years - i've just noticed this because of the new year.

$daydate = date("d");
$monthdate = date("m");
$yeardate = date("Y");

$day_10 = ($daydate - 10);
$daydate10 = $yeardate . "-" . $monthdate . "-" . $day_10;
$daydate10_start = strtotime(date("$daydate10 00:00:00"));
$daydate10_end = strtotime(date("$daydate10 23:59:59"));

PHP:

Anyone know of any functions to do the same thing as this but works for any date?

 

You can get a date 10 days ago as such, if that's what you mean:

$ten_days_ago = time()-(86400*10);
$format = date("M d Y h:i:s", $ten_days_ago);

Code (markup):

 

Thanks for your reply cozmic but if the current time is 5:00 on the 3rd Jan 2010 then it'll give me the timestamp of 5:00 on the 24th December but i want the time 0:00 on the 24th december.
Also, I want date to timestamp, not timestamp to date.

Anyway thanks for your help.

 

$days = -10; // Ten days ago
$timestamp = strtotime( date( "Y-m-d 00:00:01", time() + ( 86400 * $days ) ) ) ;

PHP:

Try that