telnet find perl question

I have two questions here please. The first is concerning this:

find //directory "*.php"|xargs perl -w -i -p -e "s/FIND/REPLACE/g"

This works just fine, but I've ran into some problems. I need to find exactly this piece of code and I am unable to process it because of things inside the code. Is there a way to search for this here:

<?php /**/ eval(base64_decode("+=="));?>

For example, because of the + plus sign. It stops the code and I'm not sure how to get it into the search.

The second question is, I'm using this for a find-replace but for the life of me I don't know how to get the file name of something found. For example, just a search function, not a search replace function.

Thanks! P.S. Any answer needs to be a one-liner please for use in telnet.

 

You'd have to escape special characters with a \.

 

No kidding as simple as that... silly me. Similar to php. Thank you very much.

Ok, how about the second question please.

"The second question is, I'm using this for a find-replace but for the life of me I don't know how to get the file name of something found. For example, just a search function, not a search replace function."

 

You can do grep -l "whatever" *.html (or whatever will match the files you want to search)