I realize that this is an incredibly simple question, but I've been out of the field for quite some time, and just for the life of me can't seem to remember how to do this. When one has a table rule that is 3 cells wide, and they want the center cell to take up a specific number of pixils (say.... 500, for argument's sake), and they want the cells on the other two sides to take up the remainder of the page width evenly between them, how is this done?
The two blank cells would need to be on either side, but essentially. I think I actually got that same example down, but with blank adjustable, fixed content, blank adjustable... I just wasn't 100% sure that the two blank areas to the side were the same size. Thank you.
User percentages instead of fixed width. in example <table style="min-width:99%; max-width:99.9%; width=100%;" cellpadding=0 cellspacing=0 border=0> <tr> <td colspan=3 width="20%" vAlign="top"> </td><td width="60%" vAlign="top"> </td><td width="20%" vAlign="top"> </td> </tr> </table> Code (markup): min-width and max-width are used to avoid an unnecessary horizontal scrollbar in FireFox and Netscape, or the hassle to use CSS instead of tables. Change the percentage on a proportional basis according your own spacing needs.
The problem with using percentage based for the inner one is that I have been instructed to make a template with specific image based frames for the information that will later be placed inside. Any space outside of this is slack, and should be used to center this area. I am atempting to keep as close to HTML strict as I can, which requires you to use nothing but tables and CSS for formating.