Sytax Error

Hello,
First of all , sorry if my question sounds foolish , i am new to php .
I have the following code that generates a syntax error on line 13 and i am trying to find a solution for a few hours now ..any help is appreciated.

<?php 

        $referrer = $_SERVER['HTTP_REFERER'];
        if(preg_match("/[\.\/](google|yahoo|bing|geegain|mywebsearch|ask|alltheweb)\.[a-z\.]{2,5}[\/]/i",$referrer,$search_engine)){
        $referrer_query = parse_url($referrer);
        $referrer_query = $referrer_query["query"];
        $q = "[q|p]";
        preg_match("/".$q."=(.*?)&/",$referrer,$keywords);
        $keywords = urldecode($keywords[1]);
        
        if(isset($keywords)){
        
        $result = mysql_query ("SELECT number FROM keywords WHERE keywords="$keywords" limit 1") or die (mysql_error());
        $check = mysql_num_rows($result);
        
        if ($check=="0") {
        $new_row = mysql_query("INSERT INTO keywords VALUES ('1','$keywords')");  
            } 
        else {
        $update=mysql_query("UPDATE keywords SET number=number+1 WHERE keywords="$keywords"");

            }
        }

    }

?>

Code (markup):

Thank you.

 

$result = mysql_query ("SELECT number FROM WHERE keywords="$keywords" limit 1") or die (mysql_error());

should be

$result = mysql_query ("SELECT number FROM WHERE keywords='$keywords' limit 1") or die (mysql_error());

 

also using `` for column name is advisable
$result = mysql_query ("SELECT number FROM WHERE `keywords`='$keywords' limit 1") or die (mysql_error());