Struck in MySQL query results

I have been using MySQL as backend to my PHP codings.
Since I found a struck in fetching query results.
If Im try to pass a query from function(PHP) like "SELECT count(col1) FROM mytable WHERE col1>55;" means, the possible results are:
1) Error - if query is wrong
2) 0 - if condition not satisfied
3) count result - if found 1 or more results

Here My problem is, if the result may be on 1 or 2 means how can I check its ERROR or 0 from my code?

 

mysql_error() will return you the error if any. This is how you can fetch the results.

 

Say this is your query string:

$query = "SELECT count(col1) FROM myTable WHERE col1 >55"; // This is the query that will be executed on the database
$execute = mysql_query($query) or die (mysql_error()); // The mysql_query() function executes the query specified, but if it does not work (or die), then display the error MySQL gives. Simple as.

// To find out of the number returned was 0, do this (I think)

$row = mysql_fetch_array($execute);

$num_returned = $row[0];

if($num_returned == 0) {
echo "Statement returned 0;
}

PHP:

 

Almost like this one, but Im using these statements inside a function getCount("); - so dont want to echo mysql_error() at all.

If Im getting values from that function it may return ERROR or VALUE . How can identify if 0 and ERROR or differ ?
If u so interested solve it for me pls ?

 

Can't say anything unless we see the code of function getCount().