strpos($content,")") ???

It seems that php cannot undrestand the second bracket is a string and not end of function.

Any idea guys?

 

I dont get what you mean?
What do you want the second bracket to be?

Edit: I get what you mean now sorry, lol took a second.

You could substitute them with varibles like.

$var = ")";
strpos($content,"$var")

Code (markup):

 

What version of php do you have? echo strpos ('asdf)asdf', ')'); prints "4" for me.

 

I use version 5.

I will try that $var, thanks.

 

It's most likely you have an error before the line where you call strpos, because if you enclose the ) in either single or double quotes, it'll work just fine.

 

whats wrong to it
run this and check.
<?
$content = "find the bracket ) here";
echo strpos($content,")");
?>

 

That code works fine for me with PHP 5.1.3, it returns 17.

 

Ran it as well, works just fine for me. I use PHP 4.