SQL Help! Please

Does any kow how I can resolve this error.

Warning: mysql_result(): Unable to jump to row 0 on MySQL result index 38
/home/content/l/i/n/link2work2330/html/classes/mysql_db_engine.php on line 91


Line 91: return mysql_result(mysql_query($sql,$this->connection),0);

 

1. Can we see the whole code?
2. Is it possible the query is not returning anything?

 

Here is the entire error messege:

Warning: mysql_result(): Unable to jump to row 0 on MySQL result index 38 in /home/content/l/i/n/link2work2330/html/classes/mysql_db_engine.php on line 91

Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /home/content/l/i/n/link2work2330/html/classes/mysql_db_engine.php on line 91

Here is the code:

* mysql_rows_affected
*/
function rows_affected() {
return mysql_rows_affected();
}

/**
*
*
*/
function fetch_array($resource) {
$res = mysql_fetch_array($resource,MYSQL_ASSOC);
return $res;
}

/*
*
* get single value from select
*/
function get_scalar($sql) {
return mysql_result(mysql_query($sql,$this->connection),0);
}

/**
* Enter description here...
*
* @param mysqli result $result
* @return int
*/
function num_rows($result) {
return mysql_num_rows($result);
}

/**
* Enter description here...
*
* @param mysql result $result
* @param int $row_number
* @return int
*/
function data_seek($result,$row_number) {
return mysql_data_seek($result,$row_number);
}

function affected_rows() {
return mysql_affected_rows($this->connection);
}

/**
*
* close database connection
*/
function close() {
return mysql_close();
}


This is more of the code, it actually 164 lines long.

 

what is the code from lines 88,89,90,91,92