small php code help needed

Hi
I need help with the php code

<?php
$current_url = "http://" .$_SERVER['HTTP_HOST'] .$_SERVER['REQUEST_URI'];
print $current_url
?>

this is gonna return a url ( a string ) with exactly this pattern ( so dont have to worry much about the logics fo the url returned)
http://yoursite.com/node/123/idontwant_thisstuff
or could be
http://yoursite.com/?q=node/123/idontwant_thisstuff

Basically i want to run a loop to get rid of "/idontwant_thisstuff" i.e anything after node/87/...
should get deleted. i.e i just want url two main things
first the word "node"( ofcourse the base url also http://yoursite.com/ ) and the numeric value proceeding it.

eg http://yoursite.com/node/1/events ---> http://yoursite.com/node/1
http://yoursite.com/node/123423423/groups -----> http://yoursite.com/node/123423423

please if someone could do this
Having working since morning on drupal, and this is the last step(except some css work) to achieve my goals.
please help me out
Thanks
Himtuna

 

I am not sure you are pulling the right information to do what you want and I do not have enough experience to write the code from scratch without testing it.

I think a better approach might be contained in this script fragment which I think does what does what you want. Remove the remarks (//) to debug it for your use.

Post back and let us know if that worked.

 

<?php
$url = "$_SERVER['HTTP_HOST'] .$_SERVER['REQUEST_URI'];"
$str = explode("/",$url);
echo "$str[1]/$str[2]/$str[3]";
?> 

PHP:

 

I used this (drupal specific)

<?php
if ( arg(0) == 'node' && is_numeric(arg(1)) ) {
  $my_id = arg(1);
  echo $my_id ; 
}

?>

Code (markup):

All you would have to do is echo the domain and ?node= . Course will require php formatting in drupal. And I'm not sure if it works with extra crud on the query string.

 

Thanks a lot to every one.
@shallowink
Your code does what I wanted.
How to get the base url of the the drupal

 

This is what I was looking for.
Thanks