Simple code giving error

Discussion in 'PHP' started by Theozard, Mar 15, 2007.

  1. #1
    Parse error: syntax error, unexpected $end in C:\Program Files\xampp\htdocs\trial.php on line 11
    Not much of a programmer. Please help :)
     
    Theozard, Mar 15, 2007 IP
  2. tinkerbox

    tinkerbox Peon

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    #2
    missing double qoute
    echo "the value is 100;
    Code (markup):
    to
    echo "the value is 100";
    Code (markup):
     
    tinkerbox, Mar 15, 2007 IP
  3. Theozard

    Theozard Active Member

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    #3
    i check everything and forget this :p

    Thanks for the reply
    Problem solved!
     
    Theozard, Mar 15, 2007 IP
  4. tinkerbox

    tinkerbox Peon

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    #4
    try using phpeditor. Using editor like notepad is not much help for beginner.
    With editor, you can read and notice syntax error easier. Im using HAPEdit, its free :)
     
    tinkerbox, Mar 16, 2007 IP