Showing image from database

I have an image uploader to MySQL. I have it set up so that they can go to: address.com/content/images?id=1 and it will download image 1.

How do I set it up so that it will display the image inside the browser instead of downloading it? I want to display it within a page so it needs to be <img src>

here's the code

<form method="post" enctype="multipart/form-data">
<table width="350" border="0" cellpadding="1" cellspacing="1" class="box">
<tr>
<td width="246">
<input type="hidden" name="MAX_FILE_SIZE" value="2000000">
<input name="userfile" type="file" id="userfile">
</td>
<td width="80"><input name="upload" type="submit" class="box" id="upload" value=" Upload "></td>
</tr>
</table>
</form>


<?php
if(isset($_POST['upload']) && $_FILES['userfile']['size'] > 0)
{
$author   = $info['edits'];
$fileName = $_FILES['userfile']['name'];
$tmpName  = $_FILES['userfile']['tmp_name'];
$fileSize = $_FILES['userfile']['size'];
$fileType = $_FILES['userfile']['type'];

$fp      = fopen($tmpName, 'r');
$content = fread($fp, filesize($tmpName));
$content = addslashes($content);
fclose($fp);

if(!get_magic_quotes_gpc())
{
    $fileName = addslashes($fileName);
}
$query = "INSERT INTO upload (author, name, size, type, content ) ".
"VALUES ('$author', '$fileName', '$fileSize', '$fileType', '$content')";

mysql_query($query) or die('Error, query failed');

echo "<br>File $fileName uploaded<br>";
}
?>
<br /><br />




<?php
if(isset($_GET['id']))
{
// if id is set then get the file with the id from database

$id    = $_GET['id'];
$query = "SELECT name, type, size, content " .
         "FROM upload WHERE id = '$id'";

$result = mysql_query($query) or die('Error, query failed');
list($name, $type, $size, $content) =                                  mysql_fetch_array($result);

header("Content-length: $size");
header("Content-type: $type");
header("Content-Disposition: attachment; filename=$name");
echo $content;

exit;
}

?>
 <?php
	$username = $_COOKIE['ID_my_site']; 
	$check = mysql_query("SELECT * FROM users WHERE username = '$username'")or die(mysql_error()); 
	$info = mysql_fetch_array( $check );
	$author = $info['edits'];
$query = "SELECT id, name FROM upload WHERE author='$author'";
$result = mysql_query($query) or die('Error, query failed');
if(mysql_num_rows($result) == 0)
{
echo "You currently have no images uploaded<br />";
}
else
{
while(list($id, $name) = mysql_fetch_array($result))
{

echo "<img src=main.php?id=$result[id] alt=\"".
                htmlspecialchars($result[type].".")."\">"
				?>
<a href="main.php?id=<?php echo $id;?>"><?php echo $name;?></a> <br>
<?php
}
}
?>


<?php
if(isset($_GET['id']))
{
// if id is set then get the file with the id from database

$id    = $_GET['id'];
$query = "SELECT name, type, size, content " .
         "FROM upload WHERE id = '$id'";

$result = mysql_query($query) or die('Error, query failed');
list($name, $type, $size, $content) =                                  mysql_fetch_array($result);

header("Content-length: $size");
header("Content-type: $type");
header("Content-Disposition: attachment; filename=$name");
echo $content;

exit;
}

?>

PHP:

My sad attempt is in there.

Any help is appreciated.

 

remove this thing

header("Content-Disposition: attachment; filename=$name");