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Script for random image or flash file?

Discussion in 'Programming' started by Johnburk, Nov 3, 2005.

  1. mitchandre

    mitchandre Peon

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    #21
    give me all the names of the images you are using and all the names of flash files your using.
    SEMrush
     
    mitchandre, Nov 4, 2005 IP
    SEMrush
  2. Johnburk

    Johnburk Peon

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    #22
    names are:

    image0.jpg
    image1.jpg
    image2.jpg
    image3.jpg
    image4.jpg


    flash0.swf
    flash1.swf
    flash2.swf
    flash3.swf

    I also tried the following code, but get the following in my error log


    "File does not exist: /home/website/public_html/test/<"
    Code (markup):

    
    <?php 
    $r_swf[]="flash0.swf" 
    $r_swf[]="flash1.swf" 
    $r_swf[]="flash2.swf" 
    $swf = $r_swf[ rand(0,2) ]; 
    ?> 
    <embed name="Movie1" src="<? echo $swf; ?>" quality="high" bgcolor="#FFFFFF"
        width="269" height="367"
        type="application/x-shockwave-flash"
        pluginspage="http://www.macromedia.com/shockwave/download/index.cgi?P1_Prod_Version=ShockwaveFlash">
      </embed>
    
    PHP:
     
    Johnburk, Nov 4, 2005 IP
  3. Johnburk

    Johnburk Peon

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    #23
    Put this in a php file, put in on your server

    <?php
    $random_number = rand(1,9);
    echo '<object width="550" height="400">
    <param name="movie" value="flash' . $random_number . '.swf">
    <embed src="flash' . $random_number . '.swf" width="550" height="400">
    </embed>
    </object>';
    ?> 
    PHP:
    Then add
    <iframe src="myflash.php" width="550" height="400" scrolling="no" frameborder="0">Sorry, your browser does not support IFrames!</iframe> 
    Code (markup):
    And it works. Only for flash, but it works :)
     
    Johnburk, Nov 4, 2005 IP
  4. mitchandre

    mitchandre Peon

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    #24
    This will incorporate both. ;)

    
    <?php
    $imageorflash = rand(1,2);
    If (imageorflash == 1){
    	$random_number = rand(0,3);
    	echo '<object width="550" height="400">
    	<param name="movie" value="flash' . $random_number . '.swf">
    	<embed src="flash' . $random_number . '.swf" width="550" height="400">
    	</embed>
    	</object>';
    	}
    else {
    	$random_integer = rand(0,4); // Assumes you have images from image0 to image4
    	echo '<img src="http://www.domain.com/image', $random_integer, '.jpg"></img>'; //point to the correct domain/folder, this assumes .jpg but can be easily changed
    	}
    ?>
    
    PHP:
     
    mitchandre, Nov 4, 2005 IP
  5. Johnburk

    Johnburk Peon

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    #25
    Thanks alot :D You have been so kind to help me
     
    Johnburk, Nov 4, 2005 IP
  6. mitchandre

    mitchandre Peon

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    #26
    did it work?
     
    mitchandre, Nov 4, 2005 IP