Regular expression: Replacement question

hi RE gurus,

i have a string
"before [hide] some secret words [/hide] after"

how can i use preg_replace and return the two strings below

1. "before
-- reply to view content -- after"

2. "before some secret words after"

Thanks for guiding

 

<?php
$string = <<<STRING
before [hide] some secret words [/hide] after
STRING;

//outputs - "before -- reply to view content -- after"
$string1 = preg_replace("@\[hide\](.*)\[/hide\]@", "-- reply to view content --", $string);

//outputs - "before some secret words after"
$string2 = preg_replace("@\[hide\]|\[/hide\]@", "", $string);

?>

PHP:

 

I think on the string1 one he wants to get rid of the text between the faux tags and replace them with a constant string.

 

@ SmallPotatoes

Thanks, fixed - don't know whats wrong with me today, keep missing things.

 

Thanks, but this work for

but not

how can i get ride of "\n" or "<br>"?

 

Sure add the 's' modifier.

<?php
$string = <<<STRING
'start hide topic [hide] somehid decontent

[/hide] after
STRING;

//outputs - "before -- reply to view content -- after"
$string1 = preg_replace("@\[hide\](.*)\[/hide\]@s", "-- reply to view content --", $string);

//outputs - "before some secret words after"
$string2 = preg_replace("@\[hide\]|\[/hide\]@s", "", $string);

echo $string1;

?>

PHP: