regular expression problem

Hallo!

$text = "hare krishna";
$text = preg_replace('/\W+/', '-', $text);

PHP:

$text return hare-krishna, as expected with DASH.
But if I use Cyrillic, the result is not the same, no DASH.

I tried

$text = preg_replace('/\w+/ui', '-', $text);

PHP:

and it is not yet.

Can anyone help me how to separate words with a hyphen in Latin and Cyrillic?

Thanks!

 

If replacing spaces with dashes is what you are looking to achieve, str_replace will work on all languages.

 

Well if there will always be a space why not just use a str_replace?

Glen

 

I want to filter invalid characters for words like ()*&^% and so on. I wont only words, separated by DASH.
I will use the expression for URL address.

Thanks

 

Without an actual sample of the text and the result you are trying to achieve, It is hard to test which functions you should use. Have a look at the overloaded mb_* functions, maybe one of them can help you:

http://uk3.php.net/manual/en/mbstring.overload.php

 

Or you can use u modifier:

$text = preg_replace('/\W+/mu', '-', $text);

PHP:

Variant 2:

$text = preg_replace('/[^a-zа-я0-9]+/miu', '-', $text);

PHP:

Regards