hey guys.. I have it set up as 3 select drop downs Month Day Year in birthdate on the html side so far but I want that 3 variable will be merge into 1 field in my database..actually i have my code below i just dont know how to fix the error; "Undefined index: d_birth in c:\program files\easyphp1-8\www\pinkbox\addclub_members.php on line 20" can anyone help me...thanks! <?php $con = mysql_connect("localhost","pbclub","theclub"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("pinkbox", $con); $bcode=$_POST['bcode']; $idno=$_POST['idno']; $name=$_POST['name']; $address=$_POST['address']; $dbirth = '0000-00-00'; if(checkdate($_POST['m_dbirth'], $_POST['d_dbirth'], $_POST['y_dbirth'])) { $dbirth = $_POST['y_dbirth'] . '-' . $_POST['m_dbirth'] . '-' . $_POST['d_birth']; } $branch=$_POST['branch']; $reg_date = '0000-00-00'; if(checkdate($_POST['m_reg_date'], $_POST['d_reg_date'], $_POST['y_reg_date'])) { $reg_date = $_POST['y_reg_date'] . '-' . $_POST['m_reg_date'] . '-' . $_POST['d_reg_date']; } $school=$_POST['school']; $contact_num=$_POST['contact_num']; $email=$_POST['email']; $query="INSERT INTO club_members (bcode, idno, name, address, dbirth, branch, reg_date, school, contact_num, email) VALUES ('$bcode', '$idno', '$name','$address','$dbirth','$branch','$reg_date','$school','$contact_num','$email')"; $result=mysql_query($query); if($result){ echo "Successful!"; echo "<BR>"; echo "<a href='club_members.php'><font face=arial size=2>View Club Members</font></a>"; // link to view guestbook page } else { echo " <html> <head></head> <bgcolor=pink> <font face=bangle size=5><b>ERROR!</b> <br><br> <font face=arial narrow size=2><b> <a href='register.php'>back to registration</a> </b></font> </body> </html> "; } mysql_close(); ?>