Regex

Any idea how to extract all the files (1.css, 2.css, 3.css) from this string using regex?

$string = '@import url("1.css"); @import url(2.css); @import "3.css"; @import url("4.css") all;';

PHP:

 

preg_match_all("/url(\"(\d+.css)\"/",$out); - i thins so

 

neah...does not work at all..

I got very close but still far away

preg_match_all ( '/@import[^>]+\p{P}(.*?).css/si', $string, $sheet );

PHP:

 

Someone....?! I really need this

 

preg_match_all('/import\s+(?:url\()?["\']?([^"\'\)]+)/i', $string, $css);

print_r($css[1]);

PHP:

 

Of course it works . If my project will convert, I'll have to split with you . Thanks again nico.

 

hey nico...any idea why your regex fails to extract in this situation (a valid css import):

$str = '@import: url(\'test.css\');';
function searchCSSImports ( $str )
{
		preg_match_all ( '/import[^>]+(?:url\()?["\']?([^"\'\)]+)/i', $str, $sheet );
		return $sheet [ 1 ];
}
	

echo '<pre>';
print_r ( searchCSSImports ( $str ) );
echo '</pre>';

PHP:

 

'/@import\s*:?\s*(?:url\()?["\']?([^"\'\)]+)/i'

PHP:

Works for me with these examples. (Didn't test others, if there are any)

$str = '
	@import: url(\'test.css\');
	@import: \'test2.css\';
	@import url("1.css"); 
	@import url(2.css);
	@import "3.css";
	@import url("4.css") all;';

PHP:

 

Thank you very much for the speedy reply.