Regex

Hello guys i want to replace the value at the "0x1" part from this three findstr function in a file. I have tried doing it for an hour but i still can't do it so i need a lil help...thanks

findstr /i /C:"0x1" C:\reg1.txt
findstr /i /C:"0x1" C:\reg2.txt
findstr /i /C:"0x1" C:\reg3.txt

This is what i tried below
$batch_contents = preg_replace('~"([a-z0-9_ -]+)"\sC:\reg1.txt ~i', '$newArgument.\sC:\reg1.txt', $batch_contents);

$batch_contents = preg_replace('~"([a-z0-9_ -]+)"\sC:\reg2.txt ~i', '$newArgument.\sC:\reg2.txt', $batch_contents);

 

If its a constant 0x1 then str_replace might be easier. Can you post what you have exactly and your desired result, your above post is a little confusing.

 

Basically i'm doing an edit function
i want this line -> findstr /i /C:"0x1" C:\reg1.txt
to be changed to - > findstr /i /C:"0x2" C:\reg1.txt for example..

 

If it's not a constant, something like this would suffice:

<?php
    $string = 'findstr /i /C:"0x1" C:\reg1.txt';
    $replacement_text = 'replaced';
    
    $string = preg_replace('#(?<=findstr\s/i\s/C:")(.*?)(?="\sC:\\\\reg1.txt)#i', $replacement_text, $string);
    echo $string;
?>

PHP:

 

Thanks alot, it works! Thank you everyone!