Read the source of a webpage

i want to get the source code of this webpage:
http://www.pornhub.com/view_video.php?viewkey=5984790cc93d68a4f181

I hv tried like this;

<?php
$fh = fopen("http://www.pornhub.com/view_video.php?viewkey=5984790cc93d68a4f181", "r") or die("***CANNOT READ***");

$fullstring;
while(!feof($fh))
{
    $output = htmlspecialchars(fgets($fh, 1024));
	#echo ("$output");
	$fullstring = $fullstring."".$output; 
}

echo $fullstring;
?>

PHP:

But it says it is not possible to read the file!
here the demo of this code: http://getvidz.info/demo.php -> NOT working

But , this works fine... when tried using this :
http://demo.efoxt.com/4zerandibbuy/

How to do such a thing! ... i just want to read the source;
if possible.... pls provide sample code

 

mate use CURL...

here is a little function I wrote for u..

function get_content($url)  
{ 
	$ch = curl_init();  
	curl_setopt ($ch, CURLOPT_URL, $url);  
	curl_setopt ($ch, CURLOPT_HEADER, 1); 
	curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/5.0 (Windows; U; MSIE 7.0; Windows NT 6.0; en-US)');  

	curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1);
	ob_start();  
	curl_exec ($ch);  
	curl_close ($ch);  
	$string = ob_get_contents();  
	ob_end_clean();  
	return $string;      
}

//usage sample
$url = "http://www.pornhub.com/view_video.php?viewkey=5984790cc93d68a4f181";
$mydata = get_content($url); 
echo $mydata; 

PHP:

btw the code is not tested

 

thx
works fine

 

Mate, use CURLOPT_RETURNTRANSFER rather than output buffering.

 

I suggest you read the PHP manual, http://www.php.net/manual/en/curl.examples-basic.php
Read the comment made by "cmnajs at gmail dot com"

 

glad that I helped

 

only source? why not file_get_contents?