problems arise from upgrading php

The scripts which were written for php 4.3.0 do not seem to work with php 5.1.2
Or did I forget something when I configured php 5.1.2?

With php 4.3.0 writing something in the password field produces whatever I wrote and "OK", but with 5.1.2 the variable does not pass.

<?php
echo $var.<br>;

if (!$var){
echo "<form name=login method=post action='test.php'>"; echo "<input type=password name=var>";
echo "<br><input type=submit value='click'>";
echo "</form>";
}
else{
echo "OK";
}

?>

 

$var=$_POST['var'];

PHP:

 

you can do something like this

<?

if(isset($_POST['submit'])) {

$var = $_POST[var];

echo "OK";
} else {
echo 'Your html form';
}
?>

PHP:

 

Use this :-

<?
	if(isset($_POST['click']))
	{
		echo $_POST['var'];
		exit;
	}
	else
	{
		echo "OK";
	}

	echo "<form name='login' method='post' action='test.php'>"; 
		echo "<input type='password' name='var'>";
		echo "<br><input type='submit' value='click' name='click'>";
	echo "</form>";
?>

PHP:

 

Also, there are quite a few changes implied in the change from PHP4 to PHP5. Have a look at the PHP manual.

 

Thank you, this problem was solved.
But I could not find any mention of this in the PHP manual in the chapter which dealt with changes in migrating from 4 to 5.

Now I) ran into something else (which wasn't mentioned in the manual, either). This is about error messages.

If I write a script with a mistake in it (an extra parenthesis),

<?php
echo "This is a php-script";
{
?>

PHP 4 gives an error message:
Parse error: parse error, unexpected $ in /server/apache/htdocs/errormessage.php on line 3

PHP 5 returns a blank page. This is quite inconvenient, when trying to locate something extra or someting missing in a 300 line script.