Problem with search engine.

When i need to add search engine to my page, i have discovered one problem, but i cant get answer, because all code are fine, but i have error - Couldn't execute query

<?

  // Get the search variable from URL

  $var = @$_POST['q'];
  $trimmed = trim($var); //trim whitespace from the stored variable

// rows to return
$limit=10;

// check for an empty string and display a message.
if ($trimmed == "")
  {
  echo "<p>Please enter a search...</p>";
  exit;
  }

// check for a search parameter
if (!isset($var))
  {
  echo "<p>We dont seem to have a search parameter!</p>";
  exit;
  }

//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost", "user", "password");
mysql_select_db("database") or die("Unable to select database"); //select which database we're using

// Build SQL Query  
$query = "SELECT * FROM tables WHERE field_1 like \"%$trimmed%\" OR field_2 like \"%$trimmed%\"
  order by field_1"; // EDIT HERE and specify your table and field names for the SQL query

$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);

// If we have no results, offer a google search as an alternative

if ($numrows == 0)
  {
  echo "<h4>Results</h4>";
  echo "<p>Sorry, your search: &quot;" . $trimmed . "&quot; returned zero results</p>";

// google
echo "<p><a href=\"http://www.google.com/search?q="
  . $trimmed . "\" target=\"_blank\" title=\"Look up
  " . $trimmed . " on Google\">Click here</a> to try the
  search on google</p>";
  }

// next determine if s has been passed to script, if not use 0
  if (empty($s)) {
  $s=0;
  }

// get results
  $query .= " limit $s,$limit";
  $result = mysql_query($query) or die("Couldn't execute query");

// display what the person searched for
echo "<p>You searched for: &quot;" . $var . "&quot;</p>";

// begin to show results set
echo "Results";
$count = 1 + $s;

// now you can display the results returned
  while ($row= mysql_fetch_array($result)) {
  $title = $row["1st_field"];

  echo "$count.)&nbsp;$title";
  $count++;
  }

$currPage = (($s/$limit) + 1);

//break before paging
  echo "<br />";

  // next we need to do the links to other results
  if ($s>=1) { // bypass PREV link if s is 0
  $prevs=($s-$limit);
  print "&nbsp;<a href=\"$PHP_SELF?s=$prevs&q=$var\">&lt;&lt;
  Prev 10</a>&nbsp&nbsp;";
  }

// calculate number of pages needing links
  $pages=intval($numrows/$limit);

// $pages now contains int of pages needed unless there is a remainder from division

  if ($numrows%$limit) {
  // has remainder so add one page
  $pages++;
  }

// check to see if last page
  if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {

  // not last page so give NEXT link
  $news=$s+$limit;

  echo "&nbsp;<a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 &gt;&gt;</a>";
  }

$a = $s + ($limit);
  if ($a > $numrows) { $a = $numrows; }
  $b = $s + 1;
  echo "<p>Showing results $b to $a of $numrows</p>";
  
?> 

PHP:

 

Replace:

 $result = mysql_query($query) or die("Couldn't execute query");

PHP:

With:

 $result = mysql_query($query) or die(mysql_error());

PHP:

And tell us what the exact error is.

 

Right, and sometime you need to print out the query then paste it in your MySQL console (phpmyadmin) to find more error description.

 $result = mysql_query($query) or die(mysql_error()."<br>query: $query");

PHP:

 

SELECT * FROM tables WHERE field_1 like \"%$trimmed%\" OR field_2 like \"%$trimmed%\" order by field_1

should be...

SELECT * FROM tables WHERE field_1 like '%$trimmed%' OR field_2 like '%$trimmed%' order by field_1

ie. single quotes not double