Problem with my code. Parse error

I am trying to call a record from a db so that I can amend it in a form. I keep getting the following message:

Parse error: parse error in /chroot/home/TM340484/public_html/blog/editentry3.php on line 42

Line 42 is the end of my page.

The variable is being passed to the receiving page, but I can't see what the error is in my code. I have pared the code to just two fields to try to narrow it down, but can't get it. I'm a beginner at this so could do with some help.

<?php
//queries the database using the variable value
$amendarticle = mysql_query("SELECT * FROM article WHERE article_id='$article_id'" )or die(mysql_error());
//Tests that there is a result from the query(amendarticle) and outputs to screen

while ($myrow = mysql_fetch_array($amendarticle)) 

{
mysql_close();
?>


<form name="getentry" action="editentry.php" method="get"  target="_self">

<input type="hidden" name="article_id"  value="<? echo $myrow["article_id"]; ?>"><? echo $myrow["article_id"]; ?><br>
 
<input type="text" name="article_title"  size="60" maxlength="60" value="<? echo $myrow["article_title"]; ?>"><br>



<input type="reset" value="Clear" name="reset"><br>
<input type="submit" value="Submit" name="submit"  ><br>


</form>

Code (markup):

If anyone could help I would be grateful. I can't do the next bit until I can see that I can recall a record.

Thanks for your help

 

If that's all of you code the first problem is you are not opening the first php tag, all you php sections should begin with <?php (<? will work but <?php is more obvious IMO)

 

Sorry, I missed the opening tag from the code posted, but it is there. Even when I changed the <? to <?php I still get the same problem. I am not familiar enough with php to see what is wrong.

Any further ideas?

 

I think you've missed the closing of the loop.

<?php
}
?>

 

Thanks JRJR, I had just noticed it, then checked here to tell everyone, and you had already provided the answer.

Thanks

 

Cool. If you have anymore problem shoot it here.