Printing A to Z using for statement

I was just playing around the for statement in php to output the letters "A" to "Z".

<?php
for ($letters=A; $letters <= Z; $letters++)
{
print ("$letters, ");
}
?>

The above code works fine if "$letters <= Y" or any other letter before "Z". But if I use "Z" it goes beyond Z and includes double letters like "AA, AB, AC till YZ.

Anyone know how to make it stop at "Z".

 

I take another route

for ($i=1;$i<=26;$i++) {
if (!isset($letters)) { $letters=A; }
print ("$letters, ");
$letters++;
}

PHP:

 

Thanks!
W'd appreciate if you could let me know how it works in reverse order "Z to A"
I tried

<?php
for ($i=26;$i>=1;$i--) {
if (!isset($letters)) { $letters=Z; }
print ("$letters, ");
$letters--;
}
?>

PHP:

It just prints "Z" 26 times. But the above code works fine with numbers "26 to 1".

 

you dont have to change the loop to this for ($i=26;$i>=1;$i--) {
because we just need the for loop to print 26 alphabet thats all.
but its no hurt.

decrement? cant seems to find a better way...Maybe you can try this:

for ($i=1;$i<=26;$i++) {
if (!isset($letters)) { $letters=A; }
$string .= ",$letters ";
$letters++;
}
$string = strrev($string);

// to test it
print $string;

PHP: