preg_replace - how to strip all links

I would like to strip all links from a website, and change all links to #.

how i can change all links like a href="http://digitalpoint.com" toan simple a href="#" ?!

 

Something like that:

$text = preg_replace('/href=".+?"/sm', 'href="#"', $text);

PHP:

Will work if quotes are ", if single qoutes:

$text = preg_replace('/href=\'.+?\'/sm', 'href="#"', $text);

PHP:

 

The link doesn't have to be in single or double quotes though, it can be directly after the "a href=" statement and still be valid.

This may be a more elegant solution that will also remove any javascript embedded in the link.

<?php
$text = <<<END
	this <a href="test.html">is</a> 
	<a href='test.html'>a</a> 
	<a href="test.html">test</a> !!! 
END;

print $text . "<br />";

$text = preg_replace('/<a href=.+?>/', '<a href="#">', $text);

print $text;
?>

Code (markup):

 

AFAIK there can be alteration in REGEX, but I don't know regex so much to use it, so problem with single double or no quotes can be solved with 1 preg_replace.

I suppose this code

$text = preg_replace('/<a href=.+?>/', '<a href="#">', $text);

PHP:

will not work with links like this

 

I code all my codes like this ..

$search='#(<BASE HREF=")(.*)(wstub.archive.org/">)#e';
$data = preg_replace($search,"('')",$data);


I mean i code the search_replace like this:

(begin)(match)(end)

Can somebody translate this to me in the () () () , because you only push me deeper into darkness...


how '/<a href=.+?>/', will look in ()(.*)() ?!

(href=".*)(.*)(") ?!