preg_replace 2 strings same code same function

I'm trying to replace 2 parts of a javascript code

line1
line2

$function preg_replace(find, replace, '');
echo $function;

How do I write the same code to replace line 2, which will look for a different item and replace it with something different

 

You probably don't even need preg_replace(). You should use str_replace() if you know exactly what you are looking as it will be faster.

$strJavaScript = <<<EOF
// Insert a whole bunch
// of JavaScript here
EOF;

$strSearch1 = '** Edit: Script code to find **';
$strSearch2 = '** Edit: More script code to find **';

$strReplace1 = '** Edit: New value for $Search1 **';
$strReplace2 = '** Edit: New value for $Search2 **';

print(str_replace(
  array($strSearch1, $strSearch2), 
  array($strReplace1, $strReplace2), 
  $strJavaScript);

Code (markup):

If you actually need regular expression pattern matching then do this:

$strJavaScript = <<<EOF
// Insert a whole bunch
// of JavaScript here
EOF;

$strSearch1 = '** Edit: Script to find **';
$strSearch2 = '** Edit: More sript to find **';

$strReplace1 = '** Edit: New value for $Search1 **';
$strReplace2 = '** Edit: New value for $Search2 **';

print(ereg_replace(
  $strSearch1, $strReplace1, ereg_replace(
    $strSearch2, $strReplace2, $strJavaScript));

Code (markup):