Preg_match_all need to find <img src="...._50_50_ ...">

Can't get preg_match_all working

First I use curl to get the source

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);
$src = curl_exec ($ch);
curl_close ($ch); 
$src = ereg_replace("\n", "", $src);

$find = '/<img src="*._50_50_.*"/';
preg_match_all($find, $src, $m);

$img=$m[1][0];

Code (markup):

Any suggestions??

 

$find = '/<img src="([a-zA-Z0-9\/\_\-\.]+)_50_50_([a-zA-Z0-9\/\_\-\.]+)"/';
preg_match_all($find, $src, $m);

print_r ( $m );

Code (markup):

 

thx guitarFix,

But I don't have the img src yet. I got more than with my code, now it returns

Array ( [0] => Array ( ) [1] => Array ( ) [2] => Array ( ) )

I tested with

print_r ( $m );
		$img=$m[1][0];
		echo "test ".$m[0][2];
		echo $m[0][0];
		echo $m[0][1];
		echo $m[1][1];

Code (markup):

With no luck, Still learning preg_match_all.

 

ok found a solution

$find = '/([\:a-zA-Z0-9\/\_\-\.]+)_50_50_([a-zA-Z0-9\/\_\-\.]+)"/';
		preg_match_all($find, $src, $m);
		
		//print_r ( $m );
		$img=$m[1][0];
		$img.="_50_50_";
		$img.=$m[2][0];
		echo $img;//testing
		$msg .= '<img src="'.$img.'">';
		echo $msg;

Code (markup):

I added \: and read the array $m. About the array $m is this the right way???