preg_match

...<img src="/img_box/wind-13x13/w045.gif" alt="NE" width="13" height="13" /> 22 kmh
                      </p>...

PHP:

I want to get the speed (here it is 22). My idea is to get second and third charecters before kmh. But i don not have an idea how to do it? Can you help me?
note: "/img_box/wind-13x13/w045.gif", "NE" and "22" are not static.

 

solved

echo "<br>";

<? $data = "The party will start at 22 kmh";
preg_match_all('/(\d+)\s*(kmh|kml)/', $data, $match, PREG_PATTERN_ORDER);
echo "Full: <br>";
print_r($match[0]);
echo "<p>Raw: <br>";
print_r($match[1]);
echo "<p>Tags: <br>";
print_r($match[2]);
?> 

PHP:

output:

Full: <br>Array
(
    [0] => 22 kmh
)
<p>Raw: <br>Array
(
    [0] => 22
)
<p>Tags: <br>Array
(
    [0] => kmh
)

HTML:

 

I would add the <img> marker before the \d so the pattern is more specific.

/<img[^>]+>\s*(\d+)\s*(kmh|kml)/is

Code (markup):

 

Thanks, it helped me solving a similar problematic code

 

The original code was here http://php.about.com/od/advancedphp/ss/php_preg_3.htm