preg_match question

I had a "eregi_replace" code before. Now updating the scripts with preg_match..

I was using this piece of the script to convert "Some Hotel Name.html" to look like "Some-Hotel-Name.html" with the code downbelow at some parts of the page.

$space = ' ';
$replace = '/-/';
$row[hotelname] = preg_replace($replace, $space, $row[hotelname]);
$hotelname = preg_replace($replace, $space, $hotelname);
$originalhotelname = preg_replace($space, $replace, $row[hotelname]);

the var $space is basically a space.. But could not work it out.. what do I have to use as space ? $space ='/ /'; does not work. I get "Some//-//Hote//-//Name.html"

 

You can try this

<?php
$sefurl_separator = '-';// Search engine friendly URL separator

$from = $row['hotelname'];
$output = preg_replace('/([^a-z0-9\.]+)/i', $sefurl_separator, $from);

echo $output;// This should be >>> Some-Hotel-Name.html
?>

PHP:

 

echo str_replace(' ', '-', 'Some Hotel Name.html');

PHP:

No need to use regex when its not needed.

 

problem sorted with ;

echo str_replace(' ', '-', 'Some Hotel Name.html');

Thanks all