preg_match help

$html='<style>

.active {
	color:#ffffff;
	background:#0A246A;
	cursor:default;
}

#template {
	text-align:center;
	width:145px;
	border:1px solid #aaa;
	float:left;
	margin:5px;
	
}
	#template #info {
		height:100px;
		width:98%;
		padding: 2px;
	}

	#template h6 {
		margin:0;
		padding:0;
		border:0;
	}
	
	#template #use {
		width:100%;
		background:#aaa;
		color:#fff;
		display:block;
		font-weight:bold;
		text-decoration:none;
		cursor:pointer;
	}
	
	#template #use input {
		height:10px;
		width:10px;
	}

</style>

<script>
function change_rss(t){
	f = document.getElementById("rss");
	if(t == "html"){
		f.style.display = "none";
	}else{
		f.style.display = "inline";
	}
}
</script>

PHP:

Hi I need to extract only css class not css ID from this string. For example, from above string, I need a expression so that it gives output

array('.active')

PHP:

becoz .active is the only css class.

Pls help

 

Here is a starting point (I suck bad at regex):

preg_match_all('~\.(.*?)\s~',$html,$matches);

echo '<pre>';
print_r($matches[0]);
echo '</pre>';

PHP:

Put that under you HTML variable. Unfortunately it picks up anything in the script element too, so you'll need some more help, but its still a start.

 

Thanks for the help. I need more precise

Thanks again

 

preg_match_all('~[\s\}>](\.[\w-]+)\s*\{~', $html, $matches);

echo '<pre>', print_r($matches[1], true), '</pre>';

PHP:

... this should be pretty precise.