preg_match and regex problem

Hi,
My function;

 function alfanumeric($ifade) {

    if(preg_match('/([^\w|\s{0,1}])+/i', $ifade)) 
        return false; 
    else                                            
        return true;
  }

  echo  alfanumeric("sample user name");

PHP:

I want just words, digits, white spaces.

Function is most return false for double or high white spaces.

but how ?

thanks...

 

function alfanumeric($ifade)
{
    return preg_match('/^[a-z0-9\s]+$/i', $ifade);
}

PHP:

\w also matches under scores, so if you only want letters, numbers, and spaces, the above should work.

 

The function doesn't return false for double white spaces.

" " like it...

 

Not sure what you mean.

if (alfanumeric('Hello "quote"'))
{
	echo 'Is alfanumeric';
}
else
{
	echo 'Is not alfanumeric';
}

PHP:

Outputs: Is not alfanumeric

Which is true.

 

Thank you this true but I want exaclty that.

// I have got this variable
$data="            sample user         name";

// I want this
$data="sample user name";

// I dont want this
// white space + white space + white space 

Code (markup):

 

I wouldn't bother the user and throw an error for this. I'd just remove the double spaces and continue.

$data = preg_replace('/\s{2,}/', ' ', $data);

PHP:

If you still want to check for double spaces in the function, you can do:

function alfanumeric($ifade)
{
    return preg_match('/^[a-z0-9\s]+$/i', $ifade) AND !preg_match('/\s{2,}/', $ifade);
}

PHP:

 

thank you thank you thank you