Populate an array from a list to get

I have a .txt file with

link[|]21/12/2009[|]text
linkB[|]10/01/2010[|] txt B
linkC[|]23/02/2010[|]Txt C

Code (markup):

I like to get this

<li><a href="link"><span>21/12/2009</span> text</a></li> 
<li><a href="linkB"><span>10/01/2010</span> txt B</a></li> 
<li><a href="linkC"><span>23/02/2010</span></a></li> 

Code (markup):

with the following function

	function getTickerContent(){
		$open = "content/tickerContent.txt";
		$filedata = file_get_contents ($open);
		list($data, $text, $link)  = explode("[|]",$filedata); 	
.....
.....

	return $tickerContent;
	}

PHP:

Any tips? code suggestions??

 

tx digitalpoint (sounds familar),

i have produce this

function getData(){
		$open = "content/tickerContent.txt";
		$filedata = file_get_contents($open);
		$data = explode("\r", $filedata);
		foreach ($data as $line) {
			$output[] = explode('[|]', $line);
		}
		return $output;
	}

function getTickerContent(){
	
	$tickerContents = getData();
	$res = '<ul>';
	foreach ($tickerContents as $tickerContent) {
		$res .= '<li><a href="'.$tickerContent[2].'"><span>'.$tickerContent[0].'</span>'.$tickerContent[1].'</a></li>';
	}
	$res .= '</ul>';
	return $res;
	}
echo getTickerContent();

PHP:

 

or you can use preg_replace()

<?php

function getTickerContent(){
$tickerContent = preg_replace("@(.*)\[\|\](.*)\[\|\](.*)@", "<li><a href=\"$1\"><span>$2</span>$3</a></li>", file_get_contents("content/tickerContent.txt"));
return $tickerContent;
}

echo getTickerContent();

?>

PHP: