PHP5 problem, how do I fix it?

Okay, I'm getting the following error

Line 289 is this

$spell_recipe[$i]['item_name'] = adr_get_lang($recipe_list[$i]['item_name']);

PHP:

and the segment of code it is from is this

			//Recipe list
			$sql = "SELECT item_id, item_name, item_type_use, item_owner_id
				FROM " . ADR_SHOPS_ITEMS_TABLE. "
				WHERE item_type_use = '110'
				AND item_owner_id ='1'";
			$result = $db->sql_query($sql);
			if( !$result )
				message_die(GENERAL_ERROR, 'Could not obtain recipe information', "", __LINE__, __FILE__, $sql);
			$recipe_list = $db->sql_fetchrowset($result);

			$spell_recipe = '<select name="spell_recipe">';
                  	$spell_recipe .= '<option value = "0" >' . $lang['Adr_spells_recipe_none'] . '</option>';
                  	for( $i = 0; $i < count($recipe_list); $i++ )
                  	{
				$spell_recipe[$i]['item_name'] = adr_get_lang($recipe_list[$i]['item_name']);
				$spell_selected = ( $items['spell_linked_item'] == $recipe_list[$i]['item_id'] ) ? 'selected' : '';
				$spell_recipe .= '<option value = "'.$recipe_list[$i]['item_id'].'" '.$spell_selected.' >' . $recipe_list[$i]['item_name'] . '</option>';
                	}
                  	$spell_recipe .= '</select>';

PHP:

What is really annoying is that there is code that is pretty much identical to this which works fine.

 

change line 289 to:

$recipe_list[$i]['item_name'] = adr_get_lang($recipe_list[$i]['item_name']);

This was simply assigning to the wrong variable ($spell_recipe instead of $recipe_list).

It looks like a mistake that php4 had interpreted as something else so it didn't show as a problem.

Edit: I am assuming you have upgraded from php4 to php5 but that might not be the case!

 

Thanks, that fixed it. I had it running fine on PHP4, but it caused problems with someone else's setup on PHP5.