Php

I'm attempting to call the function inputFileTab which reads a text file and puts it into a 2d array, then return the array to the function that called it (contentResume), but so far nothing is being returned. Can anyone answer why?

Thanks

function contentResume(){
inputFileTab("files/content/resume.txt", "");
for($b=0;$b<count($contents);$b++){
print("<a href=\"files/download/".$contents[$b][0].
"\"><img src=\"".$contents[$b][1]."\"></a>");
print("<br />");
}
}


function inputFileTab($fileLocation, $nextFunction){
$file=file($fileLocation);
for($i=0;$i<count($file);$i++){
$lineExplode=explode("\t",$file[$i]);
for($x=0;$x<count($lineExplode);$x++){
$contents[$i][$x]=$lineExplode[$x];
}
}
if(function_exists($nextFunction)){
$nextFunction($contents);
}else{
return($contents);
}
}

 

Your syntax is wrong

$nextFunction($contents);

Looks like you are more familiar with javascript?

You will need to eval(); it.

 

hows eval going to return the array created by inputFileTab to contentResume?

 

Nah, this is actually valid syntax.