PHP question

Hi

Can this be done?? and if so how

I want some text to show unless 0 shows. I dont mean a zero result from the data base.

In context

eg

Brian has 4 (i want to show)

Brian has 0 (i don't want to show)

4 and 0 comes from a data base.

Really any number greater than 0 I want to show!!

Hope someone can help - if this makes sense

Regards

 

if ($number > 0){
print 'Brian has '.$number;
}

PHP:

So you are only displaying (printing) the text if the number variable is greater than zero.

-Ryan

 

I love you

 

or

if($number > 0)
{
   echo 'Brian has'.$number;
}
else
{
} 

PHP:

Regards

 

You could also do the following

if($number == 0){
    echo "Brian doesn't have any apples";
} elseif($number == 1){
    echo "Brian has one apple";
} else {
    echo "Brian has" . $number . "apples";
}

PHP:

 

Or

if ($number == 0)
{
    echo "Brian doesn't have any apples";
}
else
{
    echo "Brian has ". $number ." apple". ($number != 1 ? 's' : '') .'.';
}

PHP:

 

Alternatively, you might want to use the following:

Forget it, there are already too many above...
Just kidding.
Bye

 

Wait, wait, or maybe this.

switch($number)
{
      case 0:
         echo "Brian doesn't have any apples";
         break;
  
      case 1:
         echo "Brian has one apple";
         break;
  
      default:
         echo "Brian has" . $number . "apples";
}

Code (markup):

 

What a great selection of replies.

Thing is Brian hates F..king apples now and wants banana's

Jamie

 

Brian will have what he is given and be grateful for it!