php/mysql help needed - hiding or showing a table based on mysql

I am making a contact list php/mysql script and each contact can have up to ten websites. When I list the contacts details and for example they have one website listed it will look like this:

Website 1: foobar.com
Website 2:
Website 3:
etc etc

If there is a value present under Website 2, I want to echo a table that lists $website2, else echo nothing...

I have tried WHERE EXISTS etc but I can't seem to put it together...

Database: cls
Table: contacts

 

You won't get an answer unless you put your tables structure and current (relevant) PHP code here.

 

Select everything, and echo only when there is data

dont copy this code because it is not complete but try to understand it.

while($row = mysql_fetch_array($result))
{
$website = $row["website"];
if ($website)
{
//echo table
}
}

PHP:

 

Thanks dweebsonduty!

Here's what I did:

include 'config.php';
$query="SELECT * FROM contacts WHERE website2='$website2'";
$result=mysql_query($query);
while($row = mysql_fetch_array($result))
{
$website2 = $row["website2"];
if ($website2)
{
// table
}
}

mysql_close();

PHP: