PHP invalid ip address

Discussion in 'PHP' started by l3l00, Mar 15, 2013.

0
  1. #1
    Okay so I got a lot of work done last night and it is going well so fare, trying to connect this cart to an API.

    so I have
    $ipaddress = urlencode($_SERVER['REMOTE_ADDR']);
    Code (markup):
    it shows in the debug report 127.0.0.1 but it then says it is wrong?

    &ipAddress=127.0.0.1resource(4) of type (stream) errorFound=1&responseCode=321&errorMessage=Invalid+IP+address+of+%28Malformed+IP+Address%29+found+
    Code (markup):

     
    l3l00, Mar 15, 2013 IP
  2. Rukbat

    Rukbat Well-Known Member

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    #2
    REMOTE_ADDR is the IP address of the user. Is that what you want? (It looks like you're testing it locally.)
     
    Rukbat, Mar 15, 2013 IP
  3. innozemec

    innozemec Active Member

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    #3
    127.0.0.1 is your local compute's ip, thats why you might be getting that error
     
    innozemec, Mar 15, 2013 IP
  4. deathshadow

    deathshadow Acclaimed Member

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    #4
    Uhm, can we see the code AFTER that. I don't think the code you posted is what's generating that error... No, that code does not and could not generate a type mismatch error. I think it's something AFTER it. (and this is why snippets are USELESS for diagnosing bugs).

    Yeah, the code you posted has absolutely NOTHING to do with that error -- we need to see the REST of it!
     
    deathshadow, Mar 16, 2013 IP