php copy files

how can i copy folder1/*.* to folder2/ ?

supposing i don't know the exact file names in folder1 ..

i just want my script to copy over all the files that it can find in folder1 to folder2

Thanks

 

$source = './path/to/folder1/*.*';

function copy_files($file, $destination = './path/to/folder2/')
{
    copy($file, $destination . basename($file));
}

array_map('copy_files', glob($source));

PHP:

Untested but should work.

 

nice solution Nico

 

Now thats what I call great coding. In fact, I didnt even know a function called glob existed .

 

Good find!

 

Thank you

 

I'm having a bit trouble with syntax here .. could you please show the correct syntax to use ?

here's my final code

if (!is_dir("$login")) { mkdir ("$login"); }
$source = "templates/$template_ID/images/*.*";
function copy_files($file, $destination = '$login/images/') {
    copy($file, $destination . basename($file));
}
array_map('copy_files', glob($source));

PHP:

as you see, i use $login variable (which is already defined earlier) in the name of destination folder. Also i use $template_ID in source but it works fine.

and here is what i get as a result:

so, it doesn't change the "$login" to it's value , but instead uses "$login" as a string itself

 

Do it like this, variables are not interpolated inside single quotes:

if (!is_dir("$login")) { mkdir ("$login"); }
$source = "templates/$template_ID/images/*.*";
function copy_files($file, $destination = "$login/images/") {
    copy($file, $destination . basename($file));
}
array_map('copy_files', glob($source));

PHP:

PHP offers several types of quoting. Double quotes offer the most features, including variable interpolation and escape sequences like "\n" for a newline. With single quotes you get exactly what you put within the quotes, no special features.

 

I have tried that as well as some other combinations ..

in your exact case, here's what i get

 

I think i got the reason why this happens ..

the $login variable is defined AFTER the function is defined by the compiler, so at the time when the function being created - the variable $login does not exist yet ..

ok, then i guess i need another function instead of this, which will accept $login as an argument, and when the time comes to call the function, the $login will already be defined

so, can anyone please help me to create such a function ?

Thanks

 

Try this:

if (!is_dir($login)) { mkdir ($login); }
$source = "templates/$template_ID/images/*.*";
$destination = "$login/images/";
function copy_files($file) {
    global $destination;
    copy($file, $destination . basename($file));
}
array_map('copy_files', glob($source));

PHP:

 

Thanks

i actually have figured out to go another way like this

$cmd = "cp -rf /path1/images path2";
system($cmd);

it did all the job ))

 

That's good but it won't work on Windows. Using glob is cross-platform, hence the reason I thought it was a good find.