Perl to PHP

Ok I need some help with converting some Perl code to PHP again.

&get_input;

$alpha = $in{'alpha'};
$n=$in{'n'};
if($n eq "") {
	$n = 0;
}
$next = $n+50;

Code (markup):

The first line I'm not sure what it does.
Is "$in{'alpha'}" an array and it is getting the value in the "alpha" position?
Same with line 3? Where are the values in the array "$in" coming from?


Thanks

 

I guess that isn't the whole script?
I don't know perl, but get_input is to do with form GET?

$alpha = $_GET['alpha'];

if alpha is passed by get...

Maybe $n is $_GET

so...

$alpha = $_GET['alpha'];
$n = $_GET['n'];
if($n == NULL) {
	$n = 0;
}
$next = $n + 50;

PHP:

 

&get_input is a call to the get_input function -- probably where $in is getting set.

 

as that's the case, then star2323 it is best posting the whole script or paying someone to convert from perl-to-php if you prefer not to reveal the whole script.

P.S. instead of $_GET use $in if the fields alpha and n aren't coming from a form (using get).

Good luck!