Paying 10$ for a VERY easy script.

Could someone make me a script that will check what the referring url and if its not the refereeing url i wanted then it will show a error message instead of the site.
MUST BE EASY TO EDIT AND NOT ENCODED
price i pay: 10$

 

PM me ill do it now.

 

<?php

// Ref. site
$ref = getenv("HTTP_REFERER"); 

// site you want to test
$url = "http://www.google.com";

// the test ?

// you can add more test to see if the url is with or without www

if($ref != $url) {
     echo "Error Msg";
  }
  
  else { echo " show something else ";}
  
?>   

PHP:

send payment to my paypal

 

#!/usr/bin/perl -w-T
# The above is the path to the perl interpreter, modify to match yours!!!
# Requires at least perl 5

use CGI qw/:standard/;

# URL of referRer
my $ref = $ENV{HTTP_REFERER} || 'Unknown';

# The referRer you want?
my $wanted_ref = 'http://Somewhere/Dir/File.ext';

# The URL you want to show IF the referRer is OK?
my $url = 'http://MyDomain/MyDir/MyFile.ext';

# Check if it's the referRer you want
unless ($ref eq $wanted_ref) {
print header;
print qq/ERROR MESSAGE IN PLAIN-TEXT OR <code>HTML<\/code> HERE/;
print qq/\n/;
} else {
print redirect($url);
}

exit;

Code (markup):

Wonder how to use it?

 

This job has already been done by me.

 

Okk. Just an idea, heh.

 

So that others won't need to invest $10 in a future?