Passing Connection Object

Discussion in 'PHP' started by trixs, Feb 9, 2008.

  1. #1
    Hey Everyone,

    Im hoping someone can help me figure this out because its starting to upset me lol..

    Anyway, all im trying to do is pass a mysqli connection to other objects.
    So you create a basic connection - No issue.
    // Include connection info - this needs to be outside of view
    include("info.inc");
    
    // Create connection
    $mysqli = new mysqli($host, $user, $password, $database);
    
    if (mysqli_connect_errno()) {
       printf("Connect failed: %s\n", mysqli_connect_error());
       exit();
    }
    PHP:
    Now of course I want to pass this connection to various objects to actually do something with it. So I try:

    
    require_once('asdf.php');
    $lol = new lol($mysqli);
    
    PHP:
    Passing the object this way requires a constructor.. Ok:

      
      function __construct($mysqli) {
    
           $this->mysqli = $mysqli;
    
           if (mysqli_connect_errno()) {
              printf("Connect failed: %s\n", mysqli_connect_error());
              exit();
           }        
    
       }
    
    PHP:
    Now this will not fail but when I try to actually use the connection it tells me the result is a non object. IT would be truly nice if I could just use a pointer! I have also tried to use globals for the connection but that doesnt seem to work with php and objects.

    Anyone know what I am doing wrong?
     
    trixs, Feb 9, 2008 IP
  2. trixs

    trixs Peon

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    #2
    Figure it out!

    If anyone is interested here is what I learned:

    I had a table with a field called "index" as this program has to do with the stock market. Apparently mysql and php do not like a field name 'index'!

    the code above works fine for anyone having problems connecting.
     
    trixs, Feb 9, 2008 IP