Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING

Could someone please help. I've been trying to see the error for hours and can't see the forest for the trees. I don't know what is wrong.


Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /home/shaskel1/public_html/abcdefdev/Test.php on line 17

1. <?php
2. require_once ('config.php');
3. 
4. echo "<Carousel>\n";
5. 
6. $query  = mysql_query("select a.im_name, b.name, a.description from images a, department b where a.dpt_id = '$pid';") or die(mysql_error());
7. 
8. /* $result = mysql_query($query);*/
9. 
10. while ($row = mysql_fetch_assoc($query)) {
11. 
12.   $path = "http://tegojewelers.com";
13.
14. /* the following echo's are supposed to be one line */
15. /* <photo image="images/bridal.jpg" url="http://tegojewelers.com/Bridal/index.php" target="_self"><![CDATA[Bridal]]></photo> */
16.
17.   echo "<photo image='.$path.'/images/.$row['im_name'].";
18.   	echo "url='.$path.'.$row['name']./index.php target='_self'>";
19.  	echo "<![CDATA[.$row['description']]></photo>"; 
20. }
21. echo "</Carousel>\n";
22. 
23. mysql_close($dbh);
24. 
25. ?>

Code (markup):

Thank you
Gordon

 

Your string concatenation syntax is wrong.

Here's how:

If you want to use double quote for echo.

echo "<photo image=\"".$path."/images/".$row['im_name']."\"";
echo "url=\"".$path.$row['name']."/index.php\" target=\"_self\">";
echo "<![CDATA[".$row['description']."]></photo>";

PHP:

If you want to use single quote for echo. (I recommend using single quote for echo for html tags)

echo '<photo image="'.$path.'/images/'.$row['im_name'].'"';
echo 'url="'.$path.$row['name'].'/index.php" target="_self">';
echo '<![CDATA['.$row['description'].']></photo>';

PHP:

-----------

String concatenation is done using dot (.) operator, but you need to end the string part first before concatenating.

echo "STRING PART".$variable."STRING PART".$variable;

PHP:

To concatenate 2 variables:

echo $variable.$variable2."STRNG PART";

PHP:

If you echo statement uses double quote, and you want to display double quote, you need to escape it using backslash:

echo "I am showing a double quote \" using backslash."; 

PHP:

or better if just use single quote for echo statement. You do not have to escape then.

echo 'I am showing a double quote " using backslash.'; 

PHP:

 

Works, no more errors.
Just an empty string from database in while loop.
SQL works in database.