OR command with NOT EQUALTO help

If a user enters in (YES/NO/Don't know) I want code to continue testing if they enter in anything else I want the error message to appear.

My code below isn't working:

elseif ($hosting != "Yes" || $hosting != "No" || $hosting != "Don't know")
{
echo "Error.......";
}

PHP:

Can anyone advise.

Thanks Ian

 

You should then use AND instead of OR. This way if Any of the 3 tests fails, meaning YES/NO/DON'T KNOW is found, it will not fall into the error. Like this:

elseif ($hosting != "Yes" && $hosting != "No" && $hosting != "Don't know")
{
    echo "Error.......";
}

PHP:

 

Thanks works a treat, i also did the following more complicated route which worked....

function validate_hosting($a) {
$forbidden = array('Yes', 'No', 'Do not know');
foreach ($forbidden as $b)
if (strpos($a, $b) !== false) return true;
 return false;
}

elseif (!validate_hosting($_POST['hosting'])) {
echo "Sorry you are trying to alter the'Do you require hosting field' which you have no access to";
}

PHP:

Ian

 

If you're using a select box for "Yes","No", and "Do not know", you could simply do this then:

$forbidden = array('Yes', 'No', 'Do not know');
function validate_hosting($a) {
    global $forbidden;
    return in_array($a,$forbidden);
}

PHP:

No messy foreach loop

 

Thanks for that, yes do have combo drop down and want to make sure I don't get hit by bots, hence going OTT in checking everything.

Ian