only getting <img src=''.. > i need it to get all of images where ever src was...

hello guys, again,

i have this code that grab all imgs like that <img src='linkhere.jpg' />

but what if the img like that <img id='imgid' height='100' width='100' src='linkhere.jpg' />

so it not going to get it cuz the src at the end of the code so i want some one to update my code and make it just read the images in the page where ever the src was

here is my code

      preg_match_all("/(<img)\s (src=\"(  [a-zA-Z0-9\.;:\/\?&=_|\r|\n]   (.*)   \.(jpg|png)  )\")/isxmU", file_get_contents($url), $images)

PHP:

thanks for anyhelp

 

How about this?

/<img[^>]*>/Ui

Code (markup):

 

nope it's not working after i go trough each one of them it gives me an error

 

here is all of the code

        
		    if(preg_match_all("/(<img)\s (src=\"(  [a-zA-Z0-9\.;:\/\?&=_|\r|\n]   (.*)   \.(jpg|png)  )\")/isxmU", file_get_contents($_SESSION['url']), $images)){
		    
			/* limit number of images shown */
		    $limit = 4;
		    $i=0;
			foreach($images[3] as $image_url):
        	$valid_files = substr($image_url, -3);
	        if($valid_files == "png" || $valid_files == "jpg"){
		        if(dose_url_exists($image_url)){
					$i++;
					if($i == $limit) break;
					$image_hash = md5($image_url);
					$image_ext = substr($image_url, -3);
			
		?>
		
			<td style="float:left; margin:0 10px;"><img src="<?php echo $image_url; ?>" /></td>
			
		<?php  } } endforeach; ?>

PHP: