Notice: Undefined index error

What is wrong here?

$actual_id = ($_GET['category_id']);  // line 1 , here is the error, but what? :)

if($actual_id){
	$finded = false;
	
	for($a = 0; $a < count($first_level) && !$finded; $a++){
		if($first_level[$a]["id"] == $actual_id) $finded = true;
	}
	
	if(!$finded){
		for($b = 0; $b < count($second_level) && !$finded; $b++){
			if($second_level[$b]["id"] == $actual_id){
				$finded = true;
				$actual_id = $second_level[$b]["parent"];
			}
		}		
	}
	
	if(!$finded) $actual_id = $first_level[0]["id"];
}else{
	$actual_id = $first_level[0]["id"];
}

PHP:

 

I think your PHP configuration is set so that even E_NOTICE errors are shown,

I suggest you use this code

$actual_id = (isset($_GET['category_id']) && $_GET['category_id']);

PHP:

instead of

$actual_id = ($_GET['category_id']);

PHP:

FYI:
* You need to do something similar with the line {{{ $actual_id = $first_level[0]["id"]; }}}
* showing E_NOTICE is a good practice when on a development environment

 

Thanks a lot man, it works.

BOW!