new to php please help

I am working with a template and want to get my images from a url not on my site can i do it from this code?

function getProductDetail($pdId, $catId)
{

$_SESSION['shoppingReturnUrl'] = $_SERVER['REQUEST_URI'];

// get the product information from database
$sql = "SELECT pd_name, pd_description, pd_price, pd_image, pd_qty, pd_affurl FROM tbl_product
WHERE pd_id = $pdId";

$result = dbQuery($sql);
$row = dbFetchAssoc($result);
extract($row);

$row['pd_description'] = nl2br($row['pd_description']);

if ($row['pd_image']) {
$row['pd_image'] = WEB_ROOT . 'images/product/' . $row['pd_image'];
} else {
$row['pd_image'] = WEB_ROOT . 'images/no-image-large.png';
}

$row['cart_url'] = "cart.php?action=add&p=$pdId";

return $row;
}

Thanks for your help!

 

yes, just replace with the url and dir of where the images are located, like so:

	if ($row['pd_image']) {
		$row['pd_image'] = 'http://www.mydomainname.com/images/product/' . $row['pd_image'];
	} else {
		$row['pd_image'] = 'http://www.mydomainname.com/images/no-image-large.png';
	}

Code (markup):

of course, you have to make sure that the images have the same name as on the database.

 

thanks but that did not work

 

this is what I put in
if ($row['pd_image']) {
$row['pd_image'] = 'http://www.evitamins.com/images/products/' . $row['pd_image'];
} else {
$row['pd_image'] = 'http://www.evitamins.com/images/no-image-large.gif';
}

 

	if ($row['pd_image']) {
		$row['pd_image'] = 'http\://www.mydomainname.com/images/product/' . $row['pd_image'];
	} else {
		$row['pd_image'] = 'http\://www.mydomainname.com/images/no-image-large.png';
	}

Code (markup):

try that.